Integrand size = 11, antiderivative size = 13 \[ \int \left (-\frac {3}{x^3}+\frac {4}{x^2}\right ) \, dx=\frac {3}{2 x^2}-\frac {4}{x} \]
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Time = 0.00 (sec) , antiderivative size = 13, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \left (-\frac {3}{x^3}+\frac {4}{x^2}\right ) \, dx=\frac {3}{2 x^2}-\frac {4}{x} \]
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Rubi steps \begin{align*} \text {integral}& = \frac {3}{2 x^2}-\frac {4}{x} \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 13, normalized size of antiderivative = 1.00 \[ \int \left (-\frac {3}{x^3}+\frac {4}{x^2}\right ) \, dx=\frac {3}{2 x^2}-\frac {4}{x} \]
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Time = 0.01 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.77
method | result | size |
norman | \(\frac {-4 x +\frac {3}{2}}{x^{2}}\) | \(10\) |
gosper | \(-\frac {8 x -3}{2 x^{2}}\) | \(11\) |
parallelrisch | \(\frac {-8 x +3}{2 x^{2}}\) | \(11\) |
default | \(\frac {3}{2 x^{2}}-\frac {4}{x}\) | \(12\) |
risch | \(\frac {3}{2 x^{2}}-\frac {4}{x}\) | \(12\) |
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Time = 0.21 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.77 \[ \int \left (-\frac {3}{x^3}+\frac {4}{x^2}\right ) \, dx=-\frac {8 \, x - 3}{2 \, x^{2}} \]
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Time = 0.03 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.62 \[ \int \left (-\frac {3}{x^3}+\frac {4}{x^2}\right ) \, dx=\frac {3 - 8 x}{2 x^{2}} \]
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Time = 0.22 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.85 \[ \int \left (-\frac {3}{x^3}+\frac {4}{x^2}\right ) \, dx=-\frac {4}{x} + \frac {3}{2 \, x^{2}} \]
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Time = 0.30 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.85 \[ \int \left (-\frac {3}{x^3}+\frac {4}{x^2}\right ) \, dx=-\frac {4}{x} + \frac {3}{2 \, x^{2}} \]
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Time = 0.02 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.77 \[ \int \left (-\frac {3}{x^3}+\frac {4}{x^2}\right ) \, dx=-\frac {8\,x-3}{2\,x^2} \]
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